325 Q&As in UPDATED 1z0-071 Exam Questions Certification Test Engine to PDF [Q27-Q45]

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325 Q&As in UPDATED 1z0-071 Exam Questions Certification Test Engine to PDF

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NEW QUESTION 27
Examine these statements executed in a single Oracle session:
CREATE TABLE product (pcode NUMBER(2),pname VARCHAR2(20));
INSERT INTO product VALUES(1,’pen’);
INSERT INTO product VALUES (2,’pencil’);
INSERT INTO product VALUES(3,’fountain pen’);
SAVEPOINT a;
UPDATE product SET pcode=10 WHERE pcode =1;
COMMIT;
DELETE FROM product WHERE pcode =2;
SAVEPOINT b;
UPDATE product SET pcode=30 WHERE pcode =3;
SAVEPOINT c;
DELETE FROM product WHERE pcode =10;
ROLLBACK TO SAVEPOINT b;
COMMIT;
Which three statements are true?

The code for pen is 10.

There is no row containing fountain pen.

There is no row containing pencil.

The code for pen is 1.

The code for fountain pen is 3

There is no row containing pen

NEW QUESTION 28
View the Exhibits and examine the structure of the COSTS and PROMOTIONS tables.
You want to display PROD_IDS whose promotion cost is less than the highest cost PROD_ID in a promotion time interval.
Examine this SQL statements:

What will be the result?
Exhibit 1.

Exhibit 2.

It gives an error because the GROUP BY clause is not valid

It executes successfully but does not give the required result

It executes successfully and gives the required result

It gives an error because the ALL keyword is not valid

NEW QUESTION 29
Which three statements are true about GLOBAL TEMPORARY TABLES?

GLOBAL TEMPORARY TABLE rows inserted by a session are available to any other session whose user has been granted select on the table.

A TRUNCATE command issued in a session causes all rows In a GLOBAL TEMPORARY TABLE for the issuing session to be deleted.

A DELETE command on a GLOBAL TEMPORARY TABLE cannot be rolled back.

A GLOBAL TEMPORARY TABLE’s definition is available to multiple sessions.

Any GLOBAL TEMPORARY TABLE rows existing at session termination will be deleted.

GLOBAL TEMPORARY TABLE space allocation occurs at session start.

Global temporary tables (GTTs) in Oracle have unique properties related to session-based visibility and data persistence:
B . A TRUNCATE command issued in a session causes all rows in a GLOBAL TEMPORARY TABLE for the issuing session to be deleted: True, TRUNCATE is session-specific for GTTs and will remove all rows inserted by the session that issues the TRUNCATE command.
D . A GLOBAL TEMPORARY TABLE’s definition is available to multiple sessions: The structure of a GTT is persistent and shared across sessions, but the data within is session-specific.
E . Any GLOBAL TEMPORARY TABLE rows existing at session termination will be deleted: The data in GTTs is private for the session, and when the session ends, the data is deleted automatically.
Reference:
Oracle Database Concepts and SQL Language Reference 12c, especially the sections on temporary tables.

NEW QUESTION 30
View the Exhibit and examine the data in EMP and DEPT tables.

In the DEPT table, DEPTNO is the PRIMARY KEY.
In the EMP table, EMPNO is the PRIMARY KEY and DEPTNO is the FOREIGN KEY referencing the DEPTNO column in the DEPT table.
What would be the outcome of the following statements executed in the given sequence?
DROP TABLE emp;
FLASHBACK TABLE emp TO BEFORE DROP;
INSERT INTO emp VALUES (2, ‘SCOTT’, 10);
INSERT INTO emp VALUES (3, ‘KING’, 55);

Both the INSERT statements would fail because the constraints are automatically retrieved when the table is flashed back.

Both the INSERT statements would succeed because none of the constraints on the table are automatically retrieved when the table is flashed back.

Only the first INSERT statement would succeed because all constraints except the primary key constraint are automatically retrieved after a table is flashed back.

Only the SECOND INSERT statement would succeed because all the constraints except referential integrity constraints that reference other tables are retrieved automatically after the table is flashed back.

NEW QUESTION 31
The SYSDATE function displays the current Oracle Server date as:
21 -MAY-19
You wish to display the date as:
MONDAY, 21 MAY, 201 9
Which statement will do this?

SELECT TO _ CHAR (SYSDATE, ‘ FMDAY, DD MONTH, YYYY’) FROM DUAL;

SELECT TO _ DATE (SYSDATE, ‘ FMDAY, DD MONTH, YYYY’) FROM DUAL;

SELECT TO_ CHAR (SYSDATE, ‘ FMDD, DAY MONTH, YYYY’) FROM DUAL;

SELECT TO_ CHAR (SYSDATE, ‘ FMDAY, DDTH MONTH, YYYY’) FROM DUAL;

To format a date in Oracle SQL, TO_CHAR function is used to convert date types to string with a specified format:
* Option A: SELECT TO_CHAR(SYSDATE, ‘FMDAY, DD MONTH, YYYY’) FROM DUAL;
* This correctly applies the date format model ‘FMDAY, DD MONTH, YYYY’, which will display the date as requested: “MONDAY, 21 MAY, 2019”. FM modifier is used to remove padding blanks or leading zeros.
Options B, C, and D do not achieve the desired output:
* Option B is incorrect because TO_DATE converts a string to a date, not format a date.
* Option C and D have incorrect format strings that do not match the required output format.

NEW QUESTION 32
Which two statements are true about the SET VERIFY ON command?

It displays values for variables created by the DEFINE command.

It can be used in SQL Developer and SQL*Plus.

It can be used only in SQL*plus.

It displays values for variables prefixed with &&.

It displays values for variables used only in the WHERE clause of a query.

The SET VERIFY ON command is related to how SQL*Plus and SQL Developer display information about substitution variables:
* A. It displays values for variables created by the DEFINE command: When VERIFY is set to ON, SQL*Plus and SQL Developer will display the old and new values of a substitution variable when it is redefined using the DEFINE command or when a new value is provided for it during the session.
* B. It can be used in SQL Developer and SQL*Plus: While traditionally associated with SQL*Plus, the SET VERIFY command is also supported in SQL Developer, allowing you to control the display of substitution variable values in both environments.
References:
* Oracle SQL*Plus User’s Guide and Reference, especially the section on the SET command and
* substitution variables.

NEW QUESTION 33
Which two statements are true regarding the GROUP BY clause in a SQL statement?
(Choose two.)

You can use column alias in the GROUP BY clause.

Using the WHERE clause after the GROUP BY clause excludes the rows after creating groups.

The GROUP BY clause is mandatory if you are using an aggregate function in the SELECT clause.

Using the WHERE clause before the GROUP BY clause excludes the rows before creating groups.

If the SELECT clause has an aggregate function, then those individual columns without an aggregate function in the SELECT clause should be included in the GROUP BY cause.

NEW QUESTION 34
Which two are true about the WITH GRANT OPTION clause?

The grantee must have the GRANT ANY OBJECT PRIVILEGE system privilege to use this option.

It can be used when granting privileges to roles.

It cannot be used to pass on privileges to PUBLIC by the grantee.

It can be used for system and object privileges.

It can be used to pass on privileges to other users by the grantee.

The grantee can grant the object privilege to any user in the database, with or without including this option.

NEW QUESTION 35
Examine the description of the EMP_DETAILS table given below:

Which two statements are true regarding SQL statements that can be executed on the EMP_DETAIL TABLE?

An EMP_IMAGE column cannot be included in the ORDER BY clause.

You can alter the table to include the NOT NULL constraint on the EMP_IMAGE column.

You cannot add a new column to the table with LONG as the data type.

An EMP_IMAGE column can be included in the GROUP BY clause.

NEW QUESTION 36
View the Exhibit and examine PRODUCTS and ORDER_ITEMS tables.

You executed the following query to display PRODUCT_NAME and the number of times the product has been ordered:
SQL>SELECT p.product_name, i.item_cnt
FROM (SELECT product_id, COUNT (*) item_cnt
FROM order_items
GROUP BY product_id) i RIGHT OUTER JOIN products p
ON i.product_id = p.product_id;
What would happen when the above statement is executed?

The statement would execute successfully to produce the required output.

The statement would not execute because inline views and outer joins cannot be used together.

The statement would not execute because the ITEM_CNT alias cannot be displayed in the outer query.

The statement would not execute because the GROUP BY clause cannot be used in the inline.

NEW QUESTION 37
Which two statements best describe the benefits of using the WITH clause? (Choose two.)

It can improve the performance of a large query by storing the result of a query block having the WITH clause in the session’s temporary tablespace.

It enables sessions to reuse the same query block in a SELECT statement, if it occurs more than once in a complex query.

It enables sessions to store a query block permanently in memory and use it to create complex queries.

It enables sessions to store the results of a query permanently.

NEW QUESTION 38
Which two are true about constraints?

Constraints are enforced only during INSERT operations.

A column with a foreign key constraint can never contain a null value.

All constraints can be defined at the table or column level.

A constraint can be disabled even if the constrained column contains data.

A column with a UNIQUE constraint can contain a NULL value.

A; False. Constraints are enforced during INSERT and UPDATE operations, and by the nature of their definition, they impact DELETE operations as well (in the case of referential constraints).
B: False. A column with a foreign key constraint can contain a NULL value unless it is also constrained to be NOT NULL.
C: False. Not all constraints can be defined at the column level. For example, some constraints such as FOREIGN KEY constraints are more commonly defined at the table level.
D: True. A constraint can be disabled regardless of whether the constrained column contains data. However, re-enabling the constraint requires that all data satisfy the constraint rules.
E; True. A column with a UNIQUE constraint can indeed contain a NULL value, as NULL is considered not equal to any value, including itself. This means that multiple rows with NULL values do not violate the UNIQUE constraint.
References:
* Oracle Documentation on Constraints:
https://docs.oracle.com/database/121/SQLRF/clauses002.htm#SQLRF52271
* Oracle Documentation on Enabling and Disabling Constraints:
https://docs.oracle.com/database/121/ADMIN/clustrct.htm#ADMIN13508

NEW QUESTION 39
Examine the description of the ENPLYEES table:

Which two queries return all rows for employees whose salary is greater than the average salary in their department?

SELECT “
FROM employees
WHERE salary > ANY
SELECT AVG (salary)
EROM employees
GROUP BY department_ id);

SELECT
FROM employees
WHERE salary > AVG (salary) OVER (PARTITION BY department _ id);

SELECT”
FROM employees e1
WHERE salary >!
SELECT AVG (salary)
FROM employees e2
WHERE e1. Department _id = e2, department_ id

SELECT.
FROM
SELECT e.”, AVG (salary) OVER (PARTITION BY department id) avg_ sal
FROM employees e
WHERE salary > avg_ sal;

SELECT”
FROM employees
WHERE salary >
( SELECT AVG
(salary) FROM
employees

GROUP BY department _ id
Explanation:
To return all rows for employees whose salary is greater than the average salary in their department, you would use either a subquery or an analytic function:
Option B:
SELECT … FROM employees WHERE salary > AVG(salary) OVER (PARTITION BY department_id); This uses the window function AVG with PARTITION BY to calculate the average salary per department, and it compares each employee’s salary to this average.
Option C:
SELECT … FROM employees e1 WHERE salary > (SELECT AVG(salary) FROM employees e2 WHERE e1.department_id = e2.department_id); This correlated subquery compares each employee’s salary to the average salary in their department using a subquery to calculate the average salary for that department.
Options A, D, and E are incorrect because:
Option A: The use of ANY with the subquery does not ensure comparison with the average salary of their respective department.
Option D: This is syntactically incorrect; the subquery alias avg_sal is not accessible outside the subquery.
Option E: The subquery does not correlate with the outer query to ensure that each employee’s salary is compared to the average salary of their respective department.

NEW QUESTION 40
Examine the structure of the MEMBERStable.

Which query can be used to display the last names and city names only for members from the states MO and MI?

SELECT last_name, city FROM members WHERE state =’MO’ AND state =’MI’;

SELECT last_name, city FROM members WHERE state LIKE ‘M%’;

SELECT last_name, city FROM members WHERE state IN (‘MO’, ‘MI’);

SELECT DISTINCT last_name, city FROM members WHERE state =’MO’ OR state =’MI’;

NEW QUESTION 41
Which two are true about savepoints? (Choose two.)

After issuing a savepoints, you can roll back to the savepoint name within the current transaction.

A ROLLBACK TO SAVEPOINTcommand issued before the start of a transaction results in an error.

They make uncommitted updates visible to other sessions owned by the same user.

After issuing a savepoint, you cannot roll back the complete transaction.

You can commit updates done between two savepoints without committing other updates in the current transaction.

They make uncommitted updates visible to sessions owned by other users.

Explanation/Reference: https://www.vertica.com/docs/9.2.x/HTML/Content/Authoring/SQLReferenceManual/Statements/ SAVEPOINT.htm

NEW QUESTION 42
Examine the business rule:
Each student can take up multiple projects and each project can have multiple students.
You need to design an Entity Relationship Model (ERD) for optimal data storage and allow for generating reports in this format:
STUDENT_ID FIRST_NAME LAST_NAME PROJECT_ID PROJECT_NAME PROJECT_TASK
Which two statements are true in this scenario?

The ERD must have a 1:M relationship between the STUDENTSand PROJECTSentities.

The ERD must have a M:M relationship between the STUDENTSand PROJECTSentities that must be resolved into 1:M relationships.

STUDENT_IDmust be the primary key in the STUDENTSentity and foreign key in the PROJECTSentity.

PROJECT_IDmust be the primary key in the PROJECTSentity and foreign key in the STUDENTSentity.

An associative table must be created with a composite key of STUDENT_ID and PROJECT_ID, which is the foreign key linked to the STUDENTS and PROJECTS entities.

Explanation/Reference:
References:
http://www.oracle.com/technetwork/issue-archive/2011/11-nov/o61sql-512018.html

NEW QUESTION 43
View the Exhibit and examine the details of the PRODUCT_INFORMATION table.

Evaluate this SQL statement:
SELECT TO_CHAR (list_price, ‘$9,999’)
From product_information;
Which two statements are true regarding the output? (Choose two.)

A row whose LIST_PRICE column contains value 11235.90 would be displayed as #######.

A row whose LIST_PRICE column contains value 1123.90 would be displayed as $1,123.

A row whose LIST_PRICE column contains value 1123.90 would be displayed as $1,124.

A row whose LIST_PRICE column contains value 11235.90 would be displayed as $1,123.

NEW QUESTION 44
View the Exhibit and examine the structure of the PRODUCT_INFORMATION table. (Choose the best answer.)

PRODUCT_ID column is the primary key.
You create an index using this command:
SQL > CREATE INDEX upper_name_idx
ON product_information(UPPER(product_name));
No other indexes exist on the PRODUCT_INFORMATION table.
Which query would use the UPPER_NAME_IDX index?

SELECT product_id, UPPER(product_name)
FROM product_information
WHERE UPPER(product_name) = ‘LASERPRO’ OR list_price > 1000;

SELECT UPPER(product_name)
FROM product_information;

SELECT UPPER(product_name)
FROM product_information
WHERE product_id = 2254;

SELECT product_id
FROM product_information
WHERE UPPER(product_name) IN (‘LASERPRO’, ‘CABLE’);

Explanation

NEW QUESTION 45
Evaluate the following CREATE TABLE command:
Which statement is true regarding the above SQL statement?

It would execute successfully and only ORD_ITM_IDX index would be created.

It would give an error because the USING INDEX clause cannot be used on a composite primary.

It would execute successfully and two indexes ORD_ITM_IDX and ORD_ITM_ID PK would be created.

It would give an error because the USING INDEX is not permitted in the CRETAE TABLE command.

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The Oracle 1z0-071 exam covers a wide range of topics related to SQL and database management, including basic SQL concepts, data retrieval using SELECT statements, data manipulation using DML statements, table creation and management, and database security. It is designed for individuals who have a basic understanding of SQL and relational database concepts, and who want to improve their skills and knowledge in managing Oracle databases.

Oracle 1z0-071 certification exam is a globally recognized certification that can help candidates stand out in a competitive job market. Oracle Database SQL certification demonstrates that candidates have the skills and knowledge required to manage databases and write efficient SQL queries. It can also help candidates gain credibility with their employers and clients, which can lead to new opportunities and career advancement.

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325 Q&As in UPDATED 1z0-071 Exam Questions Certification Test Engine to PDF [Q27-Q45]
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